Saturday, 6 July 2019

Why is it possible to replace part of a BJT circuit with thevenin equivalent?


I know it's possible to replace the left side of this circuit with a thevenin equivalent, but on the left we're able to find the base voltage by the voltage divider Vcc * (R2)/(R2 + R1), which is the same as the thevenin voltage.


Doesn't this change the base voltage of the transistor since there's some base current that goes through the Rth?


enter image description here




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