Monday, 4 September 2017

transistors - Driving a MOSFET with Negative Off- State Gate Voltage


I know in practice Mosfet switches are driven by 0V to any Positive gate voltage (e.g. 0V - 15V). I am using a Mosfet pair (PMOS and NMOS) to switch 10A currents in pulses and the datasheet of MOSFET states that both PMOS and NMOS can be driven by max +20V/ -20V gate voltage.


What effects will using negative voltage to switch off a mosfet have on the performance of my circuit? Other than increased turn-on time of mosfet switches (as I need more charge to switch ON mosfet loaded with negative charge)?



Answer



Using negative voltage will increase turn-on delay time not the actual turn-on rise time. It will decrease turn-off delay time as there will be a higher voltage difference to pull the gate voltage below the threshold.


Consider a 2n7002: Cgs = 4.5e-11 F & treating as a classic capacitance with a 100R gate resistor:



enter image description here


enter image description here


The time to reach the gate threshold for turn-on is longer BUT it is quicker for turn-off.


The benefits are increase resilience to parasitic turn-on due to the miller capacitor during switching transients. Think of it like this, switching a FET is all about moving charge onto the gate-source & off. Now this could occur due to your gate-drive but it could also occur due to parasitic.


When you consider Q = CV & the \$\Delta V\$ is 2.5V for a 0:15V drive and 17.5V for a -15:15V drive, it can be seen the bipolar driver is more resisliant to charge injection, be it due to poor gate-drive design (low drive, high impedance), poor layout or high power/high speed applications.


Consider the small signal capacitance model of a FET & consider a 0V off gatedrive with a 1kR gate resistor. enter image description here


A very high gate resistor and a very sharp supply pertubation to make the point


enter image description here With a 0:15V gatedrive there is enough charge being coupled in to potentially take the gate-source voltage of one or both FET's to its threshold voltage


enter image description here With a -15:15V drive the coupling still occurs BUT now the gate voltage doesn't rise enough to potentially start conduction.


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