Here is the hybrid-$\pi$ model:
with $I_c$ and $I_b$ going in, and $I_e$ going out. The same circuit can be used for both NPN and PNP, the only thing changing being $V_{be}$ for NPN and $V_{eb}$ for PNP.
The currents direction does not change, which is what I don't understand. We know that for a PNP in active mode, $i_c = i_e+i_b$.
For a NPN in active mode, $i_e = i_b+i_c$, which corresponds to the current flow shown on the hybrid-$\pi$ model.
Why is it the same for PNP?
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