Can anyone help me to find the relation for sensitivity of wheatstone bridge using transfer function or any other methods. And why is a wheatstone bridge more sensitive when all resistors have equal value? I think what matters is the ratio of resistances and not their individual values.
Answer
Start with the Wheatstone bridge equation from wikipedia which is the subtraction of two voltage dividers.
VG=Vs(RxR3+Rx−R2R1+R2)
Sensitivity is the derivative with respect to $R_x$. You'll notice immediately that the voltage divider that doesn't have the element of interest doesn't impact the sensitivity at all. The only function of the second voltage divider is to create a set point to compare the first voltage divider to. If we take the derivative with respect to $ R_x$ we get: R3(R3+Rx)2
Wolfram Alpha Plot of Sensitivity where $R_3 =1 $

This actually shows that the maximum sensitivity is where $R_x$ trends towards 0. This assumes you don't have negative value components.
If we plot the sensitivity equation with $ R_3$ as the variable and $ R_x $ as a constant, we'll find there is a maximum right at our constant value we used for $R_x$:
Wolfram Alpha Plot of Sensitivity where $R_x=1$
This is likely where the notion that you should keep $R_3$ as close to the same value as $R_x$ comes from. The other voltage divider again just needs to match closely with the test component's voltage divider to keep the voltage difference of 0 between them.
From these two plots we can conclude that if we want to design a Wheatstone bridge with the maximum sensitivity, we should have as small of component values as possible while still keeping all of the components at approximately the same value.
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