What is the quickest way to determine the transfer function
G(s) = V_out(s)/V_in(s)
of the circuit below?
EDIT: Ok, sorry for providing so little information. This is an exercise from an old exam. I do understand laplace operations, virtual ground and stuff. I could go ahead and use Kirchhoff and what not to try to find out the transfer function. However, the solution stated that it "obviously" was G(s) = s. This is why I asked for the quickest way because I thought some of you might also think that this was "obvious"!
Answer
The full analysis of this circuit is:
\$I_c = sCV_{in}\$
\$V_{out} = -I_c (R||sL) = -I_c \dfrac{sL}{1 + s\frac{L}{R}}\$
\$\Rightarrow \dfrac{V_{out}}{V_{in}} = -\dfrac{s^2LC}{1 + s\frac{L}{R}}\$
For s large enough, this is approximately:
\$\dfrac{V_{out}}{V_{in}} \approx -sRC\$
This is obvious only if you're familiar with the well known circuit that is identical to this one but without the inductor.
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