Sunday, 19 February 2017

digital logic - How to write this boolean expression using only NOR gates?



I'm having some trouble understanding how I can convert a boolean expression to a NOR-gate only expression.


What I'm working with looks like \$T = A B' C + A' B C' + A B\$. How would I go into implementing it with NOR gates?



Answer



NAND and NOR gates are universal. So one way to solve this problem is first reduce the logic using K-maps or whatever, then draw it out with AND, OR, and NOT gates. Then use bubble pushing identity techniques to convert the gates to the desired type.


schematic


simulate this circuit – Schematic created using CircuitLab


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