I have a 1.25V 2Ah battery and I'm trying to calculate a equivalent capacitance with rated voltage of 2.7V for each of those batteries. This is what I did:
Work of Battery = $1.25V \cdot 2A \cdot 3600s = 9000J$
From the capacitor work equation:
W=0.5⋅C⋅V2
9000J=0.5⋅C⋅2.7V2
C=2469.1358F
Is this correct?
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