transfer function - Trying to determine the output of a RC-filter with load

I have a low pass filter like this:

^{simulate this circuit – Schematic created using CircuitLab}

$V_{\text{out}}$ is measured right after $R_1$, which I suppose means that it is measured over the parallel part.

$R_2$ is the load of the filter. When this circuit is measured with an oscilloscope it seems like it is not dependent on the frequency at all. I would like to investigate why.

I tried to calculate the transfer function for the filter, but I am not sure that it is right.

$$H(j\omega) = \frac{1}{R_1\left(j\omega C+\frac{1}{R_2}\right)+1}$$

I'm using $R_1 = 33\text{k}\Omega$, $R_2 = 1\text{k}\Omega$, and $C = 220\text{pF}$.

If I plot the frequency response in Matlab with this, I just get a straight line going from the origin through (1,.5), (2,1) where (Hz, H(w)) and so on.

Is this correct?

Answer

You can interpret this circuit as a voltage divider using

$$R_2 \parallel \frac{1}{j\omega C} = \frac{R_2}{j\omega R_2 C + 1}$$ and $R_1$. The transfer function is therefore

$$H(j\omega) = \frac{R_2 \parallel \frac{1}{j\omega C}}{R_2 \parallel \frac{1}{j\omega C} + R_1} = \frac{\frac{R_2}{j\omega R_2 C + 1}}{\frac{R_2}{j\omega R_2 C + 1} + R_1} = \frac{R_2}{R_2 + R_1(j\omega R_2 C + 1)}$$

If you divide numerator and denominator by $R_2$ this is the same expression you calculated, but I think it's easier to understand the filter using my result. As $\omega \to 0$

$$H(j\omega) = H(0) = \frac{R_2}{R_2 + R_1}$$ which is what you would expect for a simple voltage divider using $R_1$ and $R_2$. As $\omega \to \infty$ the denominator dominates and $|H(j\omega)| \to 0$. This is a low pass filter so the output should depend on the frequency (provided you sweep to a high enough frequency).

Here is your circuit in CircuitLab setup so that you can simulate it within CircuitLab:

^{simulate this circuit – Schematic created using CircuitLab}

And here is the frequency sweep on the circuit as reported by CircuitLab (click to make it larger):

You can use this to verify your Matlab code. If you post your Matlab code we might also be able to help you find a problem with it.