Tuesday, 9 February 2016

capacitor - Impedance load matching


Notes so far


So I've done this so far, and know one of the components is a 50ohm resistor. However I dont know where to go from here. How do i decide if its an inductor or a capacitor?
This is a past paper exam so im aware the other component is a 125nH inductor... but how do i get to that?



Answer



\$Z_L=10+\frac{1}{j\omega C}\$ turns out 10+j20, well it can't. \$\frac{1}{j\omega C} = \frac{-j}{\omega C}\$ , so it has to be negative. On the source side the conjugate complex would give a positive imaginary number, so an inductor.


$$Z_L=R_L+\frac{1}{j\omega C_L}=R_L-\frac{j}{\omega C_L}$$ $$Z_L={Z_S}^*$$ $$Z_S=R_L-\frac{1}{j\omega C_L}=R_L+\frac{j}{\omega C_L}$$ $$Z_S=R_S+j\omega L_S$$ $$R_S=R_L , \ \omega L_S=\frac{1}{\omega C_L}$$


No comments:

Post a Comment

arduino - Can I use TI's cc2541 BLE as micro controller to perform operations/ processing instead of ATmega328P AU to save cost?

I am using arduino pro mini (which contains Atmega328p AU ) along with cc2541(HM-10) to process and transfer data over BLE to smartphone. I...