Sunday, 26 January 2020

circuit analysis - finding output resistance of CB amplifier with ro


I have this CB amplifier circuit below


enter image description here


This is the small signal equivalent circuit arranged to find the output resistance R_out with the r_o included


enter image description here


Here is my analysis below to find the output resistance R_out


vx=ro(ixgmvπ)+Re(ix+vπrπ)

vx=ix(ro+Re)+(Rerπgmro)vπ
vπ+Re(ix+vπrπ)=0
thereforevπ=rπrπ+1Reix
after some rearragements vxix=Rout=ro+Re+(gmroRerπ)(rπRerπ+1)
I tried to manipulate my results but it does not come out to the same formula in the book which is below: vxix=Rout=ro+Rerπ+(Rerπ)gmro



can somebody please tell what am doing wrong?? thanks in advance for all the help.



Answer



For those who are not familiar with a small-signal linearized T-model take look here: http://www.ittc.ku.edu/~jstiles/412/handouts/5.6%20Small%20Signal%20Operation%20and%20Models/The%20Hybrid%20Pi%20and%20T%20Models%20lecture.pdf


http://www.ittc.ku.edu/~jstiles/412/handouts/5.6%20Small%20Signal%20Operation%20and%20Models/section%205_6%20%20Small%20Signal%20Operation%20and%20Models%20lecture.pdf


You made a mistake here


vπ+Re(Ix+vπrπ)=0


Solve for $v_\pi$


vπ+ReIx+Revπrπ=0


vπrπ+ReIxrπ+Revπ=0


vπrπ+Revπ=IxRerπ



vπ(rπ+Re)=IxRerπ


vπ=IxRerπrπ+Re=IxRx


Also, you can look here:


BJT common-base output resistance derivation


Calculation of output impedance of CE emitter bias configuration( unbypassed) with r_0


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