Friday, 27 September 2019

Max Voltage for Speaker of Given Power Rating


I have been looking into the design of loudspeaker drivers and would like to know how to determine the maximum voltage which can be delivered to a given speaker.


From Ohm's law we know that P = V^2 / R. Therefore with for a speaker of any given power rating it would seem that max voltage could be determined by the formula:


V = sqrt(P * R)


Therefore for an 8ohm speaker with a power rating of 10 watts, it would seem that max voltage is around 9 volts. (sqrt(8 * 10 = 80) = 8.944 ~= 9)


What I'd like to know is which voltage measurement this refers to out of the following:


-Peak (where the speaker could handle a range of 0v -> 9v)


-RMS (where the speaker could handle an RMS value of 9v)


-Peak-to-peak (where the speaker could handle a range of -9v -> 9v)



If anyone could clarify this for me I'd greatly appreciate it.




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