Friday, 25 March 2016

power - Phase Difference


$$i_1 = sin(wt +45^0) $$ $$ i_2 = -sin(wt +60^0)$$


Question : what is the phase difference dows i1 lead i2


My method


1 ) Eliminate minus sign that is i2 = sin(wt + 60 + 180 ) = sin(wt + 240 )


My answer is that i1 leads i2 by 45 - 240 = -195


but correct answer is i1 leads i2 by +165 deg




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