$$i_1 = sin(wt +45^0) $$ $$ i_2 = -sin(wt +60^0)$$
Question : what is the phase difference dows i1 lead i2
My method
1 ) Eliminate minus sign that is i2 = sin(wt + 60 + 180 ) = sin(wt + 240 )
My answer is that i1 leads i2 by 45 - 240 = -195
but correct answer is i1 leads i2 by +165 deg
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