power - Phase Difference

$$i_1 = sin(wt +45^0)$$ $$i_2 = -sin(wt +60^0)$$

Question : what is the phase difference dows i1 lead i2

My method

1 ) Eliminate minus sign that is i2 = sin(wt + 60 + 180 ) = sin(wt + 240 )

My answer is that i1 leads i2 by 45 - 240 = -195

but correct answer is i1 leads i2 by +165 deg