My preamp in my acoustic guitar died after I put the battery in backwards. I need to replace it, and fast. Piezos have incredibly high output impedance (5+ mohm) so a buffer circuit is used to knock the impedance down to a sane level.
I tried building this circuit and while it works, it lacks any sort of bass amplification:
I didnt have a 100k resistor, so r3 is 170k. I also didnt have a .1uf, so c1 is 4.7uf. I tried raising the r2 to 5mohm and it sounded the same. v+ is 9v and vb+ is 4.5v from a voltage divider. OpAmp is tl072
Any help or alteratives much appreciated!
All caps are thin film, not electrolytic
The DI Box next in the chain has an input impedance of 1mohm
Answer
The 1 Mohm bias resistor is far too low - it will load the bass signals and attenuate them much more than mid range or the treble. This happens because the piezo has capacitance and this capacitance is in series with the signal being produced. It might only be a few hundred pF and, for instance, 1nF and an external 1 Mohm bias resistor will form a high pass filter with 3dB cut-off at 159 Hz. Too high for a guitar by about an octave (low E is 82.4 Hz for example).
Try replacing the 1 Mohm with 10 Mohm and see if you get an improvement. Here's a circuit I found that uses a 10 Mohm bias resistor and so it's clear to me that that is your problem: -
You can carry on using the op-amp but note the use of the 10 Mohm resistor for biasing. Also note that C1 is not required. Here's another guitar piezo JFET amp that uses a 10 Mohm (R2) for biasing: -
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