voltage - Calculate Vth in thevenin's circuit

I want to calculate Vo by Thevenin's theorem. First I removed the RL(1k)

Now I have to calculate Vth. Can I say that Vth is 6V? or Vth=6V + voltage through 2k?

If both these options are wrong, then tell me any law or procedure to find Vth?

Answer

This is one of the easiest dependent source questions I can recall.

Just use the usual transformation of a Norton source to a Thevenin source:

^{simulate this circuit – Schematic created using CircuitLab}

Note the above conversion isn't at all remarkable.

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Do you follow the Norton source pair to Thevinin source pair conversion above? If so, then isn't this circuit relatively easy now to analyze for \$I_X\$?

If not, then perhaps you aren't prepared yet to answer a question like this?

Or, alternately, perhaps I am not aware of what mental tools you have on hand and therefore cannot know well how to help you use them for this problem?

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The above circuit folds instantly into the following:

^{simulate this circuit}

If you cannot solve for \$I_X\$ there, I'm not sure what's left to suggest. (And you should be able to work out the Thevenin resistance and voltage without any significant effort.)