Monday, 27 July 2015

operational amplifier - In an op-amp, why does Vn approach Vp until the difference is delta V / A? Why doesn't Vn just equal Vp?


In an op-amp (non-inverting), like this picture


when $V_s$ increases by $\Delta V$, $V_n$ approaches $V_p$ until the difference is $\Delta V/ A$ (where A is infinity).


Why is there the $\Delta V/ A$ difference and where does this difference come from? Why doesn't $V_n$ just equal $V_p$ (so that the difference is 0)?




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