Monday, 27 July 2015

operational amplifier - In an op-amp, why does Vn approach Vp until the difference is delta V / A? Why doesn't Vn just equal Vp?


In an op-amp (non-inverting), like this picture


when \$V_s\$ increases by \$\Delta V\$, \$V_n\$ approaches \$V_p\$ until the difference is \$\Delta V/ A\$ (where A is infinity).


Why is there the \$\Delta V/ A\$ difference and where does this difference come from? Why doesn't \$V_n\$ just equal \$V_p\$ (so that the difference is 0)?




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