voltage - Circuit analysis - laplace transform

So i have a circuit where R1 = 5 W, R2 = 2 Ω, L = 1 H, C = 1/6 F ja E = 2 V. And i need to figure out what is i_L when t=0.5s with laplace transform.
Switch opens when t=0
When t<0 i got i_L(0)=1A and U_c(0)=0 for initial values.
When t>0 circuit will look like

And now i got for KVL i got

$$E-U_L-U_R-U_C=0$$ $$E-Li_L'-\frac{i_L}{P}-\int\frac{i_L}{C}=0$$ And now in need to do laplace transform. $$E-L(sI_L-i_L(0))-\frac{I_L}{P}- \frac{1}{C}*(\frac{1}{s}*I_L)=0$$ But now i got stuck here. Thanks in advance.