Measuring an AC-voltage at the ouput of a full bridge rectifier

I've a full bridge rectifier and I put the following function into it:

$$5\sin(100\pi t)\tag1$$

So, at the output I get:

$$\left|(5-2V_d)\sin(100\pi t)\right|\tag2$$

Where \$V_d\$ is the voltage over one diode.

Now, why do I measure (with a Fluke multimeter) a DC-voltage of \$1.4\$ volts and an AC-voltage of \$0.5\$ volts. Why do I measure an AC-voltage, is it not completely DC?